x^2+x-32580=0

Solution for x^2+x-32580=0 equation:

x^2+x-32580=0

a = 1; b = 1; c = -32580;
Δ = b2-4ac
Δ = 12-4·1·(-32580)
Δ = 130321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{130321}=361$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-361}{2*1}=\frac{-362}{2}
=-181
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+361}{2*1}=\frac{360}{2}
=180
$